Distance from Petropavlovsk to Walnut Park
Distance from Petropavlovsk to Walnut Park is 10,136 kilometers. This air travel distance is equal to 6,298 miles.
The air travel (bird fly) shortest distance between Petropavlovsk and Walnut Park is 10,136 km= 6,298 miles.
If you travel with an airplane (which has average speed of 560 miles) from Petropavlovsk to Walnut Park, It takes 11.25 hours to arrive.
Petropavlovsk
Petropavlovsk is located in Kazakhstan.
| GPS Coordinates (DMS) | 54° 52´ 22.0440'' N 69° 8´ 34.8000'' E |
|---|---|
| Latitude | 54.87279 |
| Longitude | 69.14300 |
| Altitude | 143 m |
| Country | Kazakhstan |
Petropavlovsk Distances to Cities
| Petropavlovsk | Distance |
|---|---|
| Distance from Petropavlovsk to Seattle | 8,595 km |
| Distance from Petropavlovsk to Alton | 9,430 km |
| Distance from Petropavlovsk to Walnut Park | 10,136 km |
| Distance from Petropavlovsk to Algonquin | 9,040 km |
| Distance from Petropavlovsk to Cartersville | 9,830 km |
Walnut Park
Walnut Park is located in United States.
| GPS Coordinates | 33° 58´ 5.0520'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.96807 |
| Longitude | -118.22507 |
| Altitude | 48 m |
| Country | United States |