Distance from Petropavlovsk-Kamchatsky to Rochester Hills
Distance from Petropavlovsk-Kamchatsky to Rochester Hills is 7,870 kilometers. This air travel distance is equal to 4,890 miles.
The air travel (bird fly) shortest distance between Petropavlovsk-Kamchatsky and Rochester Hills is 7,870 km= 4,890 miles.
If you travel with an airplane (which has average speed of 560 miles) from Petropavlovsk-Kamchatsky to Rochester Hills, It takes 8.73 hours to arrive.
Petropavlovsk-Kamchatsky
Petropavlovsk-Kamchatsky is located in Russia.
| GPS Coordinates (DMS) | 53° 2´ 39.9840'' N 158° 39´ 2.7360'' E |
|---|---|
| Latitude | 53.04444 |
| Longitude | 158.65076 |
| Altitude | 145 m |
| Country | Russia |
Petropavlovsk-Kamchatsky Distances to Cities
| Petropavlovsk-Kamchatsky | Distance |
|---|---|
| Distance from Petropavlovsk Kamchatsky to Rochester Hills | 7,870 km |
| Distance from Petropavlovsk Kamchatsky to Duarte | 6,644 km |
| Distance from Petropavlovsk Kamchatsky to Lynnwood | 5,355 km |
| Distance from Petropavlovsk Kamchatsky to Ann Arbor | 7,877 km |
| Distance from Petropavlovsk Kamchatsky to Hazleton | 8,348 km |
Rochester Hills
Rochester Hills is located in United States.
| GPS Coordinates | 42° 39´ 30.1320'' N 83° 8´ 59.7480'' W |
|---|---|
| Latitude | 42.65837 |
| Longitude | -83.14993 |
| Altitude | 250 m |
| Country | United States |