Distance from Palm Harbor to Johannesburg
Distance from Palm Harbor to Johannesburg is 13,264 kilometers. This air travel distance is equal to 8,242 miles.
The air travel (bird fly) shortest distance between Palm Harbor and Johannesburg is 13,264 km or 8,242 miles.
If you travel with an airplane (which has average speed of 560 miles) from Palm Harbor to Johannesburg, It takes 14.72 hours to arrive.
Palm Harbor
Palm Harbor is located in United States.
| GPS Coordinates (DMS) | 28° 4´ 41.0520'' N 82° 45´ 49.3560'' W |
|---|---|
| Latitude | 28.07807 |
| Longitude | -82.76371 |
| Altitude | 20 m |
| Country | United States |
Palm Harbor Distances to Cities
| Palm Harbor | Distance |
|---|---|
| Distance from Palm Harbor to Johannesburg | 13,264 km |
Johannesburg
Johannesburg is located in South Africa.
| GPS Coordinates | 26° 12´ 8.1720'' S 28° 2´ 37.0680'' E |
|---|---|
| Latitude | -26.20227 |
| Longitude | 28.04363 |
| Altitude | 1767 m |
| Country | South Africa |