Distance from Nocera Superiore to San Antonio de la Cal
Distance from Nocera Superiore to San Antonio de la Cal is 10,488 kilometers. This air travel distance is equal to 6,517 miles.
The air travel (bird fly) shortest distance between Nocera Superiore and San Antonio de la Cal is 10,488 km= 6,517 miles.
If you travel with an airplane (which has average speed of 560 miles) from Nocera Superiore to San Antonio de la Cal, It takes 11.64 hours to arrive.
Nocera Superiore
Nocera Superiore is located in Italy.
| GPS Coordinates (DMS) | 40° 44´ 31.8120'' N 14° 40´ 32.3040'' E |
|---|---|
| Latitude | 40.74217 |
| Longitude | 14.67564 |
| Altitude | 71 m |
| Country | Italy |
Nocera Superiore Distances to Cities
| Nocera Superiore | Distance |
|---|---|
| Distance from Nocera Superiore to Ciudad Delicias | 10,200 km |
| Distance from Nocera Superiore to San Antonio De La Cal | 10,488 km |
San Antonio de la Cal
San Antonio de la Cal is located in Mexico.
| GPS Coordinates | 17° 1´ 41.9880'' N 96° 42´ 2.0160'' W |
|---|---|
| Latitude | 17.02833 |
| Longitude | -96.70056 |
| Altitude | 1553 m |
| Country | Mexico |