Distance from Muhafazat Shamal Sina' to Alexandria
Distance from Shamāl Sīnāʼ to Alexandria is 360 kilometers. This air travel distance is equal to 224 miles.
The air travel (bird fly) shortest distance between Shamāl Sīnāʼ and Alexandria is 360 km= 224 miles.
If you travel with an airplane (which has average speed of 560 miles) from Muhafazat Shamal Sina' to Alexandria, It takes 0.4 hours to arrive.
Muhafazat Shamal Sina'
Muhafazat Shamal Sina' is located in Egypt.
| GPS Coordinates (DMS) | 30° 36´ 30.4920'' N 33° 37´ 3.2880'' E |
|---|---|
| Latitude | 30.60847 |
| Longitude | 33.61758 |
| Altitude | 178 m |
| Country | Egypt |
Shamāl Sīnāʼ Distances to Cities
Alexandria
Alexandria is located in Egypt.
| GPS Coordinates | 31° 12´ 0.3240'' N 29° 55´ 7.4640'' E |
|---|---|
| Latitude | 31.20009 |
| Longitude | 29.91874 |
| Altitude | 9 m |
| Country | Egypt |
Alexandria Distances to Cities
| Alexandria | Distance |
|---|---|
| Distance from Alexandria to Cairo | 179 km |
| Distance from Alexandria to Mersa Matruh | 256 km |
| Distance from Alexandria to Hurghada | 578 km |
| Distance from Alexandria to Damietta | 182 km |
| Distance from Alexandria to Suez | 285 km |