Distance from to

Distance from Manhattan Beach to Port Alfred

Distance from Manhattan Beach to Port Alfred is 16,827 kilometers. This air travel distance is equal to 10,456 miles.

The air travel (bird fly) shortest distance between Manhattan Beach and Port Alfred is 16,827 km= 10,456 miles.

If you travel with an airplane (which has average speed of 560 miles) from Manhattan Beach to Port Alfred, It takes 18.67 hours to arrive.

Manhattan Beach

Manhattan Beach is located in United States.

GPS Coordinates (DMS)33° 53´ 5.0640'' N
118° 24´ 39.2760'' W
Latitude33.88474
Longitude-118.41091
Altitude25 m
CountryUnited States

Manhattan Beach Distances to Cities

Manhattan BeachDistance
Distance from Manhattan Beach to Nelspruit16,933 km
Distance from Manhattan Beach to Welkom16,649 km
Distance from Manhattan Beach to Durban17,112 km
Distance from Manhattan Beach to Port Alfred16,827 km

Port Alfred

Port Alfred is located in South Africa.

GPS Coordinates33° 35´ 26.0520'' S
26° 53´ 27.7440'' E
Latitude-33.59057
Longitude26.89104
Altitude24 m
CountrySouth Africa

Map of Manhattan Beach

Map of Port Alfred