Distance from Manhattan Beach to Port Alfred
Distance from Manhattan Beach to Port Alfred is 16,827 kilometers. This air travel distance is equal to 10,456 miles.
The air travel (bird fly) shortest distance between Manhattan Beach and Port Alfred is 16,827 km or 10,456 miles.
If you travel with an airplane (which has average speed of 560 miles) from Manhattan Beach to Port Alfred, It takes 18.67 hours to arrive.
Manhattan Beach
Manhattan Beach is located in United States.
| GPS Coordinates (DMS) | 33° 53´ 5.0640'' N 118° 24´ 39.2760'' W |
|---|---|
| Latitude | 33.88474 |
| Longitude | -118.41091 |
| Altitude | 25 m |
| Country | United States |
Manhattan Beach Distances to Cities
| Manhattan Beach | Distance |
|---|---|
| Distance from Manhattan Beach to Nelspruit | 16,933 km |
| Distance from Manhattan Beach to Welkom | 16,649 km |
| Distance from Manhattan Beach to Durban | 17,112 km |
| Distance from Manhattan Beach to Port Alfred | 16,827 km |
Port Alfred
Port Alfred is located in South Africa.
| GPS Coordinates | 33° 35´ 26.0520'' S 26° 53´ 27.7440'' E |
|---|---|
| Latitude | -33.59057 |
| Longitude | 26.89104 |
| Altitude | 24 m |
| Country | South Africa |