Distance from Luapula to Irosin
Distance from Luapula to Irosin is 10,828 kilometers. This air travel distance is equal to 6,728 miles.
The air travel (bird fly) shortest distance between Luapula and Irosin is 10,828 km or 6,728 miles.
If you travel with an airplane (which has average speed of 560 miles) from Luapula to Irosin, It takes 12.01 hours to arrive.
Luapula
Luapula is located in Zambia.
| GPS Coordinates (DMS) | 11° 33´ 53.3880'' S 29° 2´ 45.5640'' E |
|---|---|
| Latitude | -11.56483 |
| Longitude | 29.04599 |
| Altitude | 1244 m |
| Country | Zambia |
Luapula Distances to Cities
| Luapula | Distance |
|---|---|
| Distance from Luapula to Nabunturan | 10,935 km |
| Distance from Luapula to Calatagan | 10,488 km |
| Distance from Luapula to Aringay | 10,512 km |
| Distance from Luapula to Lupon | 10,925 km |
| Distance from Luapula to Irosin | 10,828 km |
Irosin
Irosin is located in Philippines.
| GPS Coordinates | 12° 42´ 0.4680'' N 124° 1´ 55.9560'' E |
|---|---|
| Latitude | 12.70013 |
| Longitude | 124.03221 |
| Altitude | 70 m |
| Country | Philippines |
Irosin Distances to Cities
| Irosin | Distance |
|---|---|
| Distance from Irosin to Mazabuka | 11,056 km |