Distance from Lombardy to San Giuseppe Vesuviano
Distance from Lombardy to San Giuseppe Vesuviano is 640 kilometers. This air travel distance is equal to 398 miles.
The air travel (bird fly) shortest distance between Lombardy and San Giuseppe Vesuviano is 640 km= 398 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lombardy to San Giuseppe Vesuviano, It takes 0.71 hours to arrive.
Lombardy
Lombardy is located in Italy.
| GPS Coordinates (DMS) | 45° 28´ 44.6520'' N 9° 50´ 42.8640'' E |
|---|---|
| Latitude | 45.47907 |
| Longitude | 9.84524 |
| Altitude | 110 m |
| Country | Italy |
Lombardy Distances to Cities
| Lombardy | Distance |
|---|---|
| Distance from Lombardy to Bologna | 161 km |
| Distance from Lombardy to Rome | 453 km |
| Distance from Lombardy to Florence | 219 km |
| Distance from Lombardy to Venice | 195 km |
| Distance from Lombardy to Ascoli Piceno | 419 km |
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |