Distance from Johnston Atoll to Kanggye-si
Distance from Johnston Atoll to Kanggye-si is 6,625 kilometers. This air travel distance is equal to 4,117 miles.
The air travel (bird fly) shortest distance between Johnston Atoll and Kanggye-si is 6,625 km= 4,117 miles.
If you travel with an airplane (which has average speed of 560 miles) from Johnston Atoll to Kanggye-si, It takes 7.35 hours to arrive.
Johnston Atoll
Johnston Atoll is located in United States Minor Outlying Islands.
GPS Coordinates (DMS) | 16° 45´ 24.0120'' N 169° 31´ 59.0160'' W |
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Latitude | 16.75667 |
Longitude | -169.53306 |
Altitude | -11 m |
Country | United States Minor Outlying Islands |
Johnston Atoll Distances to Cities
Johnston Atoll | Distance |
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Distance from Johnston Atoll to Kanggye Si | 6,625 km |
Kanggye-si
Kanggye-si is located in North Korea.
GPS Coordinates | 40° 58´ 10.0560'' N 126° 35´ 6.8280'' E |
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Latitude | 40.96946 |
Longitude | 126.58523 |
Altitude | 288 m |
Country | North Korea |