Distance from Iguatu to Lermontov
Distance from Iguatu to Lermontov is 9,885 kilometers. This air travel distance is equal to 6,142 miles.
The air travel (bird fly) shortest distance between Iguatu and Lermontov is 9,885 km or 6,142 miles.
If you travel with an airplane (which has average speed of 560 miles) from Iguatu to Lermontov, It takes 10.97 hours to arrive.
Iguatu
Iguatu is located in Brazil.
| GPS Coordinates (DMS) | 6° 21´ 33.9840'' S 39° 17´ 54.9960'' W |
|---|---|
| Latitude | -6.35944 |
| Longitude | -39.29861 |
| Altitude | 222 m |
| Country | Brazil |
Iguatu Distances to Cities
| Iguatu | Distance |
|---|---|
| Distance from Iguatu to Derbent | 10,282 km |
| Distance from Iguatu to Obninsk | 9,697 km |
| Distance from Iguatu to Lermontov | 9,885 km |