Distance from Hirakud to Reitz
Distance from Hīrākūd to Reitz is 8,082 kilometers. This air travel distance is equal to 5,022 miles.
The air travel (bird fly) shortest distance between Hīrākūd and Reitz is 8,082 km or 5,022 miles.
If you travel with an airplane (which has average speed of 560 miles) from Hirakud to Reitz, It takes 8.97 hours to arrive.
Hirakud
Hirakud is located in India.
| GPS Coordinates (DMS) | 21° 31´ 0.0120'' N 83° 52´ 0.0120'' E |
|---|---|
| Latitude | 21.51667 |
| Longitude | 83.86667 |
| Altitude | 155 m |
| Country | India |
Hīrākūd Distances to Cities
| Hīrākūd | Distance |
|---|---|
| Distance from Hirakud to Rustenburg | 8,039 km |
| Distance from Hirakud to Delmas | 7,953 km |
| Distance from Hirakud to Kriel | 7,918 km |
| Distance from Hirakud to Reitz | 8,082 km |
| Distance from Hirakud to Port Alfred | 8,583 km |
Reitz
Reitz is located in South Africa.
| GPS Coordinates | 27° 48´ 4.9680'' S 28° 25´ 38.1360'' E |
|---|---|
| Latitude | -27.80138 |
| Longitude | 28.42726 |
| Altitude | 1643 m |
| Country | South Africa |