Distance from Giaginskaya to McMinnville
Distance from Giaginskaya to McMinnville is 9,891 kilometers. This air travel distance is equal to 6,146 miles.
The air travel (bird fly) shortest distance between Giaginskaya and McMinnville is 9,891 km= 6,146 miles.
If you travel with an airplane (which has average speed of 560 miles) from Giaginskaya to McMinnville, It takes 10.97 hours to arrive.
Giaginskaya
Giaginskaya is located in Russia.
| GPS Coordinates (DMS) | 44° 51´ 43.4880'' N 40° 4´ 19.0200'' E |
|---|---|
| Latitude | 44.86208 |
| Longitude | 40.07195 |
| Altitude | 129 m |
| Country | Russia |
Giaginskaya Distances to Cities
| Giaginskaya | Distance |
|---|---|
| Distance from Giaginskaya to Mcminnville | 9,891 km |
| Distance from Giaginskaya to Lynnwood | 9,593 km |
| Distance from Giaginskaya to Franklin Park | 9,090 km |
| Distance from Giaginskaya to Land O Lakes | 10,043 km |
| Distance from Giaginskaya to Farragut | 9,453 km |
McMinnville
McMinnville is located in United States.
| GPS Coordinates | 45° 12´ 36.4320'' N 123° 11´ 55.3920'' W |
|---|---|
| Latitude | 45.21012 |
| Longitude | -123.19872 |
| Altitude | 48 m |
| Country | United States |