Distance from Dix-Huit Montagnes to Jeffersonville
Distance from Dix-Huit Montagnes to Jeffersonville is 8,487 kilometers. This air travel distance is equal to 5,274 miles.
The air travel (bird fly) shortest distance between Dix-Huit Montagnes and Jeffersonville is 8,487 km or 5,274 miles.
If you travel with an airplane (which has average speed of 560 miles) from Dix-Huit Montagnes to Jeffersonville, It takes 9.42 hours to arrive.
Dix-Huit Montagnes
Dix-Huit Montagnes is located in Ivory Coast.
| GPS Coordinates (DMS) | 7° 22´ 34.4640'' N 7° 26´ 17.3040'' W |
|---|---|
| Latitude | 7.37624 |
| Longitude | -7.43814 |
| Altitude | 330 m |
| Country | Ivory Coast |
Dix-Huit Montagnes Distances to Cities
| Dix-Huit Montagnes | Distance |
|---|---|
| Distance from Dix Huit Montagnes to Gallup | 10,552 km |
| Distance from Dix Huit Montagnes to Lacey | 11,274 km |
| Distance from Dix Huit Montagnes to Wilkes Barre | 7,674 km |
| Distance from Dix Huit Montagnes to Jeffersonville | 8,487 km |
| Distance from Dix Huit Montagnes to Statesville | 8,044 km |
Jeffersonville
Jeffersonville is located in United States.
| GPS Coordinates | 38° 16´ 39.2520'' N 85° 44´ 13.8480'' W |
|---|---|
| Latitude | 38.27757 |
| Longitude | -85.73718 |
| Altitude | 138 m |
| Country | United States |