Distance from Chukotskiy Avtonomnyy Okrug to San Felipe
Distance from Chukotskiy Avtonomnyy Okrug to San Felipe is 10,250 kilometers. This air travel distance is equal to 6,369 miles.
The air travel (bird fly) shortest distance between Chukotskiy Avtonomnyy Okrug and San Felipe is 10,250 km= 6,369 miles.
If you travel with an airplane (which has average speed of 560 miles) from Chukotskiy Avtonomnyy Okrug to San Felipe, It takes 11.37 hours to arrive.
Chukotskiy Avtonomnyy Okrug
Chukotskiy Avtonomnyy Okrug is located in Russia.
| GPS Coordinates (DMS) | 65° 37´ 47.4240'' N 171° 41´ 42.7920'' E |
|---|---|
| Latitude | 65.62984 |
| Longitude | 171.69522 |
| Altitude | 60 m |
| Country | Russia |
Chukotskiy Avtonomnyy Okrug Distances to Cities
| Chukotskiy Avtonomnyy Okrug | Distance |
|---|---|
| Distance from Chukotskiy Avtonomnyy Okrug to Guanare | 10,344 km |
| Distance from Chukotskiy Avtonomnyy Okrug to San Felipe | 10,250 km |
San Felipe
San Felipe is located in Venezuela.
| GPS Coordinates | 10° 20´ 23.6760'' N 68° 44´ 32.8920'' W |
|---|---|
| Latitude | 10.33991 |
| Longitude | -68.74247 |
| Altitude | 287 m |
| Country | Venezuela |