Distance from Central Luzon to Sevastopol
Distance from Central Luzon to Sevastopol is 8,598 kilometers. This air travel distance is equal to 5,343 miles.
The air travel (bird fly) shortest distance between Central Luzon and Sevastopol is 8,598 km= 5,343 miles.
If you travel with an airplane (which has average speed of 560 miles) from Central Luzon to Sevastopol, It takes 9.54 hours to arrive.
Central Luzon
Central Luzon is located in Philippines.
| GPS Coordinates (DMS) | 15° 28´ 57.9720'' N 120° 42´ 43.2000'' E |
|---|---|
| Latitude | 15.48277 |
| Longitude | 120.71200 |
| Altitude | 24 m |
| Country | Philippines |
Central Luzon Distances to Cities
| Central Luzon | Distance |
|---|---|
| Distance from Central Luzon to Kiev | 8,710 km |
| Distance from Central Luzon to Sevastopol | 8,598 km |
Sevastopol
Sevastopol is located in Ukraine.
| GPS Coordinates | 44° 35´ 19.7880'' N 33° 31´ 20.6400'' E |
|---|---|
| Latitude | 44.58883 |
| Longitude | 33.52240 |
| Altitude | 72 m |
| Country | Ukraine |