Distance from Boyle Heights to Walnut Park
Distance from Boyle Heights to Walnut Park is 8 kilometers. This air travel distance is equal to 5 miles.
The air travel (bird fly) shortest distance between Boyle Heights and Walnut Park is 8 km or 5 miles.
If you travel with an airplane (which has average speed of 560 miles) from Boyle Heights to Walnut Park, It takes 0.01 hours to arrive.
Boyle Heights
Boyle Heights is located in United States.
| GPS Coordinates (DMS) | 34° 2´ 2.0400'' N 118° 12´ 19.2600'' W |
|---|---|
| Latitude | 34.03390 |
| Longitude | -118.20535 |
| Altitude | 104 m |
| Country | United States |
Boyle Heights Distances to Cities
Walnut Park
Walnut Park is located in United States.
| GPS Coordinates | 33° 58´ 5.0520'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.96807 |
| Longitude | -118.22507 |
| Altitude | 48 m |
| Country | United States |
Walnut Park Distances to Cities
| Walnut Park | Distance |
|---|---|
| Distance from Walnut Park to West Covina | 29 km |
| Distance from Walnut Park to Whittier | 18 km |
| Distance from Walnut Park to Yucaipa | 109 km |
| Distance from Walnut Park to Apache Junction | 622 km |
| Distance from Walnut Park to Bremerton | 1,555 km |