Distance from Arkhangel'sk to Providence
Distance from Arkhangel’sk to Providence is 6,820 kilometers. This air travel distance is equal to 4,238 miles.
The air travel (bird fly) shortest distance between Arkhangel’sk and Providence is 6,820 km or 4,238 miles.
If you travel with an airplane (which has average speed of 560 miles) from Arkhangel'sk to Providence, It takes 7.57 hours to arrive.
Arkhangel'sk
Arkhangel'sk is located in Russia.
| GPS Coordinates (DMS) | 64° 32´ 24.3600'' N 40° 32´ 35.8800'' E |
|---|---|
| Latitude | 64.54010 |
| Longitude | 40.54330 |
| Altitude | 8 m |
| Country | Russia |
Arkhangel’sk Distances to Cities
| Arkhangel’sk | Distance |
|---|---|
| Distance from Arkhangel Sk to Providence | 6,820 km |
Providence
Providence is located in United States.
| GPS Coordinates | 41° 49´ 26.3640'' N 71° 24´ 46.1880'' W |
|---|---|
| Latitude | 41.82399 |
| Longitude | -71.41283 |
| Altitude | -17 m |
| Country | United States |