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Distance from Aleksandrovskoye to Rapid City

Distance from Aleksandrovskoye to Rapid City is 9,618 kilometers. This air travel distance is equal to 5,976 miles.

The air travel (bird fly) shortest distance between Aleksandrovskoye and Rapid City is 9,618 km or 5,976 miles.

If you travel with an airplane (which has average speed of 560 miles) from Aleksandrovskoye to Rapid City, It takes 10.67 hours to arrive.

Aleksandrovskoye

Aleksandrovskoye is located in Russia.

GPS Coordinates (DMS)44° 42´ 51.0120'' N
43° 0´ 2.9880'' E
Latitude44.71417
Longitude43.00083
Altitude295 m
CountryRussia

Aleksandrovskoye Distances to Cities

AleksandrovskoyeDistance
Distance from Aleksandrovskoye to Chesterfield9,668 km
Distance from Aleksandrovskoye to Cerritos11,096 km
Distance from Aleksandrovskoye to Bloomfield8,656 km
Distance from Aleksandrovskoye to Hanford10,861 km
Distance from Aleksandrovskoye to Rapid City9,618 km

Rapid City

Rapid City is located in United States.

GPS Coordinates44° 4´ 49.9440'' N
103° 13´ 51.6360'' W
Latitude44.08054
Longitude-103.23101
Altitude990 m
CountryUnited States

Map of Aleksandrovskoye

Map of Rapid City