Distance from Zeeland to Prospect Heights
Distance from Zeeland to Prospect Heights is 6,615 kilometers. This air travel distance is equal to 4,110 miles.
The air travel (bird fly) shortest distance between Zeeland and Prospect Heights is 6,615 km or 4,110 miles.
If you travel with an airplane (which has average speed of 560 miles) from Zeeland to Prospect Heights, It takes 7.34 hours to arrive.
Zeeland
Zeeland is located in Netherlands.
| GPS Coordinates (DMS) | 51° 29´ 38.5080'' N 3° 50´ 58.8480'' E |
|---|---|
| Latitude | 51.49403 |
| Longitude | 3.84968 |
| Altitude | -1 m |
| Country | Netherlands |
Zeeland Distances to Cities
| Zeeland | Distance |
|---|---|
| Distance from Zeeland to Grand Rapids | 6,413 km |
| Distance from Zeeland to Muskegon | 6,427 km |
| Distance from Zeeland to East Lansing | 6,358 km |
| Distance from Zeeland to Davenport | 6,816 km |
| Distance from Zeeland to Dekalb | 6,676 km |
Prospect Heights
Prospect Heights is located in United States.
| GPS Coordinates | 42° 5´ 43.0800'' N 87° 56´ 15.2520'' W |
|---|---|
| Latitude | 42.09530 |
| Longitude | -87.93757 |
| Altitude | 207 m |
| Country | United States |