Distance from Viterbo to San Giuseppe Vesuviano
Distance from Viterbo to San Giuseppe Vesuviano is 266 kilometers. This air travel distance is equal to 165 miles.
The air travel (bird fly) shortest distance between Viterbo and San Giuseppe Vesuviano is 266 km or 165 miles.
If you travel with an airplane (which has average speed of 560 miles) from Viterbo to San Giuseppe Vesuviano, It takes 0.3 hours to arrive.
Viterbo
Viterbo is located in Italy.
GPS Coordinates (DMS) | 42° 25´ 23.5920'' N 12° 6´ 41.0760'' E |
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Latitude | 42.42322 |
Longitude | 12.11141 |
Altitude | 358 m |
Country | Italy |
Viterbo Distances to Cities
Viterbo | Distance |
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Distance from Viterbo to Rome | 68 km |
Distance from Viterbo to Perugia | 80 km |
Distance from Viterbo to Venice | 335 km |
Distance from Viterbo to Florence | 166 km |
Distance from Viterbo to Pompei | 273 km |
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
GPS Coordinates | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
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Latitude | 40.83034 |
Longitude | 14.50342 |
Altitude | 106 m |
Country | Italy |