Distance from Tacna to Huntington Park
Distance from Tacna to Huntington Park is 7,679 kilometers. This air travel distance is equal to 4,772 miles.
The air travel (bird fly) shortest distance between Tacna and Huntington Park is 7,679 km or 4,772 miles.
If you travel with an airplane (which has average speed of 560 miles) from Tacna to Huntington Park, It takes 8.52 hours to arrive.
Tacna
Tacna is located in Peru.
| GPS Coordinates (DMS) | 18° 0´ 23.6520'' S 70° 14´ 46.5720'' W |
|---|---|
| Latitude | -18.00657 |
| Longitude | -70.24627 |
| Altitude | 597 m |
| Country | Peru |
Tacna Distances to Cities
| Tacna | Distance |
|---|---|
| Distance from Tacna to Yuma | 7,336 km |
| Distance from Tacna to Mesa | 7,203 km |
| Distance from Tacna to Ohio | 6,599 km |
| Distance from Tacna to Oregon | 8,547 km |
| Distance from Tacna to Phoenix | 7,222 km |
Huntington Park
Huntington Park is located in United States.
| GPS Coordinates | 33° 58´ 54.0480'' N 118° 13´ 30.2520'' W |
|---|---|
| Latitude | 33.98168 |
| Longitude | -118.22507 |
| Altitude | 55 m |
| Country | United States |