Distance from Petrich to San Vito dei Normanni
Distance from Petrich to San Vito dei Normanni is 470 kilometers. This air travel distance is equal to 292 miles.
The air travel (bird fly) shortest distance between Petrich and San Vito dei Normanni is 470 km or 292 miles.
If you travel with an airplane (which has average speed of 560 miles) from Petrich to San Vito dei Normanni, It takes 0.52 hours to arrive.
Petrich
Petrich is located in Bulgaria.
| GPS Coordinates (DMS) | 41° 23´ 60.0000'' N 23° 13´ 0.0120'' E |
|---|---|
| Latitude | 41.40000 |
| Longitude | 23.21667 |
| Altitude | 158 m |
| Country | Bulgaria |
Petrich Distances to Cities
| Petrich | Distance |
|---|---|
| Distance from Petrich to Fasano | 496 km |
| Distance from Petrich to Ostuni | 480 km |
| Distance from Petrich to Modugno | 539 km |
| Distance from Petrich to Brindisi | 452 km |
| Distance from Petrich to Lucera | 658 km |
San Vito dei Normanni
San Vito dei Normanni is located in Italy.
| GPS Coordinates | 40° 39´ 23.1120'' N 17° 42´ 29.3040'' E |
|---|---|
| Latitude | 40.65642 |
| Longitude | 17.70814 |
| Altitude | 111 m |
| Country | Italy |