Distance from San Miguel to Barstow Heights
Distance from San Miguel to Barstow Heights is 3,743 kilometers. This air travel distance is equal to 2,326 miles.
The air travel (bird fly) shortest distance between San Miguel and Barstow Heights is 3,743 km or 2,326 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Miguel to Barstow Heights, It takes 4.15 hours to arrive.
San Miguel
San Miguel is located in El Salvador.
| GPS Coordinates (DMS) | 13° 26´ 42.3600'' N 88° 14´ 46.0320'' W |
|---|---|
| Latitude | 13.44510 |
| Longitude | -88.24612 |
| Altitude | 792 m |
| Country | El Salvador |
San Miguel Distances to Cities
| San Miguel | Distance |
|---|---|
| Distance from San Miguel to Santa Barbara | 3,927 km |
| Distance from San Miguel to Los Angeles | 3,790 km |
| Distance from San Miguel to Ventura | 3,887 km |
| Distance from San Miguel to Boston | 3,607 km |
| Distance from San Miguel to San Jose | 4,258 km |
Barstow Heights
Barstow Heights is located in United States.
| GPS Coordinates | 34° 52´ 10.9560'' N 117° 3´ 22.1400'' W |
|---|---|
| Latitude | 34.86971 |
| Longitude | -117.05615 |
| Altitude | 780 m |
| Country | United States |