Distance from San Vito dei Normanni to San Giuseppe Vesuviano
Distance from San Vito dei Normanni to San Giuseppe Vesuviano is 271 kilometers. This air travel distance is equal to 168 miles.
The air travel (bird fly) shortest distance between San Vito dei Normanni and San Giuseppe Vesuviano is 271 km or 168 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Vito dei Normanni to San Giuseppe Vesuviano, It takes 0.3 hours to arrive.
San Vito dei Normanni
San Vito dei Normanni is located in Italy.
| GPS Coordinates (DMS) | 40° 39´ 23.1120'' N 17° 42´ 29.3040'' E |
|---|---|
| Latitude | 40.65642 |
| Longitude | 17.70814 |
| Altitude | 111 m |
| Country | Italy |
San Vito dei Normanni Distances to Cities
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |