Distance from San Giuseppe Vesuviano to Giulianova
Distance from San Giuseppe Vesuviano to Giulianova is 218 kilometers. This air travel distance is equal to 135 miles.
The air travel (bird fly) shortest distance between San Giuseppe Vesuviano and Giulianova is 218 km or 135 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Giuseppe Vesuviano to Giulianova, It takes 0.24 hours to arrive.
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates (DMS) | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |
San Giuseppe Vesuviano Distances to Cities
Giulianova
Giulianova is located in Italy.
| GPS Coordinates | 42° 45´ 13.7160'' N 13° 57´ 59.4000'' E |
|---|---|
| Latitude | 42.75381 |
| Longitude | 13.96650 |
| Altitude | 2 m |
| Country | Italy |
Giulianova Distances to Cities
| Giulianova | Distance |
|---|---|
| Distance from Giulianova to Cassano D Adda | 471 km |
| Distance from Giulianova to Bari | 301 km |
| Distance from Giulianova to Ancona | 101 km |
| Distance from Giulianova to Florence | 248 km |
| Distance from Giulianova to Capannori | 301 km |