Distance from Copan to Warrensburg
Distance from Copán to Warrensburg is 2,683 kilometers. This air travel distance is equal to 1,667 miles.
The air travel (bird fly) shortest distance between Copán and Warrensburg is 2,683 km or 1,667 miles.
If you travel with an airplane (which has average speed of 560 miles) from Copan to Warrensburg, It takes 2.98 hours to arrive.
Copan
Copan is located in Honduras.
| GPS Coordinates (DMS) | 14° 56´ 9.8880'' N 88° 51´ 52.9200'' W |
|---|---|
| Latitude | 14.93608 |
| Longitude | -88.86470 |
| Altitude | 994 m |
| Country | Honduras |
Copán Distances to Cities
| Copán | Distance |
|---|---|
| Distance from Copan to Missouri | 2,568 km |
| Distance from Copan to St Louis | 2,628 km |
| Distance from Copan to Oklahoma City | 2,433 km |
| Distance from Copan to Avon | 3,012 km |
| Distance from Copan to Dyer | 2,946 km |
Warrensburg
Warrensburg is located in United States.
| GPS Coordinates | 38° 45´ 46.0440'' N 93° 44´ 9.7800'' W |
|---|---|
| Latitude | 38.76279 |
| Longitude | -93.73605 |
| Altitude | 270 m |
| Country | United States |