Distance from San Giuseppe Vesuviano to Ciampino
Distance from San Giuseppe Vesuviano to Ciampino is 192 kilometers. This air travel distance is equal to 119 miles.
The air travel (bird fly) shortest distance between San Giuseppe Vesuviano and Ciampino is 192 km or 119 miles.
If you travel with an airplane (which has average speed of 560 miles) from San Giuseppe Vesuviano to Ciampino, It takes 0.21 hours to arrive.
San Giuseppe Vesuviano
San Giuseppe Vesuviano is located in Italy.
| GPS Coordinates (DMS) | 40° 49´ 49.2240'' N 14° 30´ 12.3120'' E |
|---|---|
| Latitude | 40.83034 |
| Longitude | 14.50342 |
| Altitude | 106 m |
| Country | Italy |
San Giuseppe Vesuviano Distances to Cities
Ciampino
Ciampino is located in Italy.
| GPS Coordinates | 41° 47´ 56.9760'' N 12° 36´ 25.9920'' E |
|---|---|
| Latitude | 41.79916 |
| Longitude | 12.60722 |
| Altitude | 132 m |
| Country | Italy |
Ciampino Distances to Cities
| Ciampino | Distance |
|---|---|
| Distance from Ciampino to Avezzano | 74 km |
| Distance from Ciampino to Acerra | 175 km |
| Distance from Ciampino to Bari | 363 km |
| Distance from Ciampino to Capannori | 282 km |
| Distance from Ciampino to Angri | 202 km |