Distance from Yamaguchi to Hermiston
Distance from Yamaguchi to Hermiston is 8,660 kilometers. This air travel distance is equal to 5,381 miles.
The air travel (bird fly) shortest distance between Yamaguchi and Hermiston is 8,660 km= 5,381 miles.
If you travel with an airplane (which has average speed of 560 miles) from Yamaguchi to Hermiston, It takes 9.61 hours to arrive.
Yamaguchi
Yamaguchi is located in Japan.
| GPS Coordinates (DMS) | 34° 10´ 42.6000'' N 131° 28´ 25.3920'' E |
|---|---|
| Latitude | 34.17850 |
| Longitude | 131.47372 |
| Altitude | 46 m |
| Country | Japan |
Yamaguchi Distances to Cities
| Yamaguchi | Distance |
|---|---|
| Distance from Yamaguchi to Oklahoma City | 10,772 km |
| Distance from Yamaguchi to Hermiston | 8,660 km |
| Distance from Yamaguchi to Yakima | 8,534 km |
| Distance from Yamaguchi to Hobbs | 10,665 km |
| Distance from Yamaguchi to Suffolk | 11,635 km |
Hermiston
Hermiston is located in United States.
| GPS Coordinates | 45° 50´ 25.4760'' N 119° 17´ 22.0560'' W |
|---|---|
| Latitude | 45.84041 |
| Longitude | -119.28946 |
| Altitude | 140 m |
| Country | United States |