Distance from Vaitupu to Jefferson City
Distance from Vaitupu to Jefferson City is 10,452 kilometers. This air travel distance is equal to 6,495 miles.
The air travel (bird fly) shortest distance between Vaitupu and Jefferson City is 10,452 km= 6,495 miles.
If you travel with an airplane (which has average speed of 560 miles) from Vaitupu to Jefferson City, It takes 11.6 hours to arrive.
Vaitupu
Vaitupu is located in Tuvalu.
| GPS Coordinates (DMS) | 7° 28´ 36.2280'' S 178° 40´ 29.1720'' E |
|---|---|
| Latitude | -7.47673 |
| Longitude | 178.67477 |
| Altitude | 19 m |
| Country | Tuvalu |
Vaitupu Distances to Cities
| Vaitupu | Distance |
|---|---|
| Distance from Vaitupu to Missouri | 10,475 km |
| Distance from Vaitupu to Jefferson City | 10,452 km |
| Distance from Vaitupu to South Dakota | 9,902 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |