Distance from Seligenstadt to Botshabelo
Distance from Seligenstadt to Botshabelo is 8,958 kilometers. This air travel distance is equal to 5,566 miles.
The air travel (bird fly) shortest distance between Seligenstadt and Botshabelo is 8,958 km= 5,566 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seligenstadt to Botshabelo, It takes 9.94 hours to arrive.
Seligenstadt
Seligenstadt is located in Germany.
| GPS Coordinates (DMS) | 50° 2´ 35.5200'' N 8° 58´ 26.1840'' E |
|---|---|
| Latitude | 50.04320 |
| Longitude | 8.97394 |
| Altitude | 112 m |
| Country | Germany |
Seligenstadt Distances to Cities
| Seligenstadt | Distance |
|---|---|
| Distance from Seligenstadt to Botshabelo | 8,958 km |
| Distance from Seligenstadt to Bloemfontein | 8,933 km |
Botshabelo
Botshabelo is located in South Africa.
| GPS Coordinates | 29° 16´ 12.5760'' S 26° 42´ 18.7200'' E |
|---|---|
| Latitude | -29.27016 |
| Longitude | 26.70520 |
| Altitude | 1404 m |
| Country | South Africa |