Distance from Sagua de Tanamo to Montego Bay
Distance from Sagua de Tánamo to Montego Bay is 365 kilometers. This air travel distance is equal to 227 miles.
The air travel (bird fly) shortest distance between Sagua de Tánamo and Montego Bay is 365 km= 227 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sagua de Tanamo to Montego Bay, It takes 0.41 hours to arrive.
Sagua de Tanamo
Sagua de Tanamo is located in Cuba.
| GPS Coordinates (DMS) | 20° 34´ 54.9840'' N 75° 14´ 29.0040'' W |
|---|---|
| Latitude | 20.58194 |
| Longitude | -75.24139 |
| Altitude | 27 m |
| Country | Cuba |
Sagua de Tánamo Distances to Cities
| Sagua de Tánamo | Distance |
|---|---|
| Distance from Sagua De Tanamo to Portmore | 339 km |
| Distance from Sagua De Tanamo to Montego Bay | 365 km |
| Distance from Sagua De Tanamo to Linstead | 330 km |
| Distance from Sagua De Tanamo to Spanish Town | 339 km |
| Distance from Sagua De Tanamo to May Pen | 358 km |
Montego Bay
Montego Bay is located in Jamaica.
| GPS Coordinates | 18° 28´ 16.1760'' N 77° 55´ 7.7880'' W |
|---|---|
| Latitude | 18.47116 |
| Longitude | -77.91883 |
| Altitude | 12 m |
| Country | Jamaica |