Distance from Lubusz to Santa Cruz de El Seibo
Distance from Lubusz to Santa Cruz de El Seibo is 7,996 kilometers. This air travel distance is equal to 4,968 miles.
The air travel (bird fly) shortest distance between Lubusz and Santa Cruz de El Seibo is 7,996 km= 4,968 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lubusz to Santa Cruz de El Seibo, It takes 8.87 hours to arrive.
Lubusz
Lubusz is located in Poland.
| GPS Coordinates (DMS) | 52° 13´ 38.8560'' N 15° 15´ 21.2760'' E |
|---|---|
| Latitude | 52.22746 |
| Longitude | 15.25591 |
| Altitude | 92 m |
| Country | Poland |
Lubusz Distances to Cities
| Lubusz | Distance |
|---|---|
| Distance from Lubusz to Santa Cruz De Barahona | 8,183 km |
| Distance from Lubusz to Santa Cruz De El Seibo | 7,996 km |
Santa Cruz de El Seibo
Santa Cruz de El Seibo is located in Dominican Republic.
| GPS Coordinates | 18° 45´ 56.1240'' N 69° 2´ 19.8960'' W |
|---|---|
| Latitude | 18.76559 |
| Longitude | -69.03886 |
| Altitude | 106 m |
| Country | Dominican Republic |