Distance from Lisakovsk to Boynton Beach
Distance from Lisakovsk to Boynton Beach is 10,523 kilometers. This air travel distance is equal to 6,539 miles.
The air travel (bird fly) shortest distance between Lisakovsk and Boynton Beach is 10,523 km= 6,539 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lisakovsk to Boynton Beach, It takes 11.68 hours to arrive.
Lisakovsk
Lisakovsk is located in Kazakhstan.
| GPS Coordinates (DMS) | 52° 32´ 49.4520'' N 62° 29´ 59.5320'' E |
|---|---|
| Latitude | 52.54707 |
| Longitude | 62.49987 |
| Altitude | 192 m |
| Country | Kazakhstan |
Lisakovsk Distances to Cities
| Lisakovsk | Distance |
|---|---|
| Distance from Lisakovsk to Anacortes | 8,794 km |
| Distance from Lisakovsk to Palm City | 10,464 km |
| Distance from Lisakovsk to Ithaca | 8,768 km |
| Distance from Lisakovsk to Boynton Beach | 10,523 km |
| Distance from Lisakovsk to Boca Raton | 10,541 km |
Boynton Beach
Boynton Beach is located in United States.
| GPS Coordinates | 26° 31´ 31.2600'' N 80° 3´ 59.1480'' W |
|---|---|
| Latitude | 26.52535 |
| Longitude | -80.06643 |
| Altitude | 11 m |
| Country | United States |