Distance from Cagayan de Oro to Aleksandrow Lodzki
Distance from Cagayan de Oro to Aleksandrów Łódzki is 10,308 kilometers. This air travel distance is equal to 6,405 miles.
The air travel (bird fly) shortest distance between Cagayan de Oro and Aleksandrów Łódzki is 10,308 km= 6,405 miles.
If you travel with an airplane (which has average speed of 560 miles) from Cagayan de Oro to Aleksandrow Lodzki, It takes 11.44 hours to arrive.
Cagayan de Oro
Cagayan de Oro is located in Philippines.
| GPS Coordinates (DMS) | 8° 28´ 55.9920'' N 124° 38´ 49.9920'' E |
|---|---|
| Latitude | 8.48222 |
| Longitude | 124.64722 |
| Altitude | 8 m |
| Country | Philippines |
Cagayan de Oro Distances to Cities
| Cagayan de Oro | Distance |
|---|---|
| Distance from Cagayan De Oro to Aleksandrow Lodzki | 10,308 km |
| Distance from Cagayan De Oro to Sopot | 10,267 km |
| Distance from Cagayan De Oro to Belchatow | 10,320 km |
| Distance from Cagayan De Oro to Mlawa | 10,196 km |
| Distance from Cagayan De Oro to Jawor | 10,541 km |
Aleksandrow Lodzki
Aleksandrow Lodzki is located in Poland.
| GPS Coordinates | 51° 49´ 10.7400'' N 19° 18´ 13.8240'' E |
|---|---|
| Latitude | 51.81965 |
| Longitude | 19.30384 |
| Altitude | 195 m |
| Country | Poland |