Distance from Belgrade to San Antonio de Los Altos
Distance from Belgrade to San Antonio de Los Altos is 9,001 kilometers. This air travel distance is equal to 5,593 miles.
The air travel (bird fly) shortest distance between Belgrade and San Antonio de Los Altos is 9,001 km= 5,593 miles.
If you travel with an airplane (which has average speed of 560 miles) from Belgrade to San Antonio de Los Altos, It takes 9.99 hours to arrive.
Belgrade
Belgrade is located in Serbia.
| GPS Coordinates (DMS) | 44° 48´ 14.4360'' N 20° 27´ 54.4680'' E |
|---|---|
| Latitude | 44.80401 |
| Longitude | 20.46513 |
| Altitude | 120 m |
| Country | Serbia |
Belgrade Distances to Cities
| Belgrade | Distance |
|---|---|
| Distance from Belgrade to Catia La Mar | 8,991 km |
| Distance from Belgrade to Maracay | 9,063 km |
| Distance from Belgrade to San Antonio De Los Altos | 9,001 km |
San Antonio de Los Altos
San Antonio de Los Altos is located in Venezuela.
| GPS Coordinates | 10° 23´ 18.7080'' N 66° 57´ 6.4440'' W |
|---|---|
| Latitude | 10.38853 |
| Longitude | -66.95179 |
| Altitude | 1396 m |
| Country | Venezuela |