Distance from to

Distance from Arganzuela to Retiro

Distance from Arganzuela to Retiro is 2 kilometers. This air travel distance is equal to 1 miles.

The air travel (bird fly) shortest distance between Arganzuela and Retiro is 2 km= 1 miles.

If you travel with an airplane (which has average speed of 560 miles) from Arganzuela to Retiro, It takes 0 hours to arrive.

Arganzuela

Arganzuela is located in Spain.

GPS Coordinates (DMS)40° 24´ 0.7560'' N
3° 41´ 46.2480'' W
Latitude40.40021
Longitude-3.69618
Altitude605 m
CountrySpain

Arganzuela Distances to Cities

ArganzuelaDistance
Distance from Arganzuela to City Center2 km
Distance from Arganzuela to Latina4 km
Distance from Arganzuela to Villa De Vallecas9 km
Distance from Arganzuela to Retiro2 km
Distance from Arganzuela to San Blas8 km

Retiro

Retiro is located in Spain.

GPS Coordinates40° 24´ 47.4120'' N
3° 40´ 59.0520'' W
Latitude40.41317
Longitude-3.68307
Altitude665 m
CountrySpain

Retiro Distances to Cities

RetiroDistance
Distance from Retiro to Oliver Valdefierro Oliver Valdefierro269 km
Distance from Retiro to Delicias271 km
Distance from Retiro to Almozara272 km
Distance from Retiro to Villa De Vallecas9 km
Distance from Retiro to Montecanal267 km

Map of Arganzuela

Map of Retiro