Distance from to

Distance from Aleksandrovskoye to Cerritos

Distance from Aleksandrovskoye to Cerritos is 11,096 kilometers. This air travel distance is equal to 6,895 miles.

The air travel (bird fly) shortest distance between Aleksandrovskoye and Cerritos is 11,096 km= 6,895 miles.

If you travel with an airplane (which has average speed of 560 miles) from Aleksandrovskoye to Cerritos, It takes 12.31 hours to arrive.

Aleksandrovskoye

Aleksandrovskoye is located in Russia.

GPS Coordinates (DMS)44° 42´ 51.0120'' N
43° 0´ 2.9880'' E
Latitude44.71417
Longitude43.00083
Altitude295 m
CountryRussia

Aleksandrovskoye Distances to Cities

AleksandrovskoyeDistance
Distance from Aleksandrovskoye to Chesterfield9,668 km
Distance from Aleksandrovskoye to Cerritos11,096 km
Distance from Aleksandrovskoye to Bloomfield8,656 km
Distance from Aleksandrovskoye to Rapid City9,618 km
Distance from Aleksandrovskoye to North Massapequa8,625 km

Cerritos

Cerritos is located in United States.

GPS Coordinates33° 51´ 30.0600'' N
118° 3´ 53.2440'' W
Latitude33.85835
Longitude-118.06479
Altitude19 m
CountryUnited States