Distance from Aguazul to Oshkosh
Distance from Aguazul to Oshkosh is 4,581 kilometers. This air travel distance is equal to 2,847 miles.
The air travel (bird fly) shortest distance between Aguazul and Oshkosh is 4,581 km= 2,847 miles.
If you travel with an airplane (which has average speed of 560 miles) from Aguazul to Oshkosh, It takes 5.08 hours to arrive.
Aguazul
Aguazul is located in Colombia.
| GPS Coordinates (DMS) | 5° 10´ 22.1520'' N 72° 32´ 49.4160'' W |
|---|---|
| Latitude | 5.17282 |
| Longitude | -72.54706 |
| Altitude | 276 m |
| Country | Colombia |
Aguazul Distances to Cities
| Aguazul | Distance |
|---|---|
| Distance from Aguazul to Lisle | 4,341 km |
| Distance from Aguazul to Oshkosh | 4,581 km |
| Distance from Aguazul to Barstow Heights | 5,628 km |
| Distance from Aguazul to Douglas | 4,826 km |
| Distance from Aguazul to South Boston | 4,119 km |
Oshkosh
Oshkosh is located in United States.
| GPS Coordinates | 44° 1´ 28.9560'' N 88° 32´ 33.3960'' W |
|---|---|
| Latitude | 44.02471 |
| Longitude | -88.54261 |
| Altitude | 237 m |
| Country | United States |