Distance from West Virginia to Seymour
Distance from West Virginia to Seymour is 474 kilometers. This air travel distance is equal to 295 miles.
The air travel (bird fly) shortest distance between West Virginia and Seymour is 474 km or 295 miles.
If you travel with an airplane (which has average speed of 560 miles) from West Virginia to Seymour, It takes 0.53 hours to arrive.
West Virginia
West Virginia is located in United States.
| GPS Coordinates (DMS) | 38° 35´ 51.4680'' N 80° 27´ 17.6400'' W |
|---|---|
| Latitude | 38.59763 |
| Longitude | -80.45490 |
| Altitude | 590 m |
| Country | United States |
West Virginia Distances to Cities
| West Virginia | Distance |
|---|---|
| Distance from West Virginia to Kentucky | 345 km |
| Distance from West Virginia to Ohio | 292 km |
| Distance from West Virginia to California | 3,417 km |
| Distance from West Virginia to New York | 601 km |
| Distance from West Virginia to Pennsylvania | 402 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |