Distance from West Virginia to San Angelo
Distance from West Virginia to San Angelo is 1,982 kilometers. This air travel distance is equal to 1,232 miles.
The air travel (bird fly) shortest distance between West Virginia and San Angelo is 1,982 km or 1,232 miles.
If you travel with an airplane (which has average speed of 560 miles) from West Virginia to San Angelo, It takes 2.2 hours to arrive.
West Virginia
West Virginia is located in United States.
GPS Coordinates (DMS) | 38° 35´ 51.4680'' N 80° 27´ 17.6400'' W |
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Latitude | 38.59763 |
Longitude | -80.45490 |
Altitude | 590 m |
Country | United States |
West Virginia Distances to Cities
West Virginia | Distance |
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Distance from West Virginia to Kentucky | 345 km |
Distance from West Virginia to Ohio | 292 km |
Distance from West Virginia to California | 3,417 km |
Distance from West Virginia to New York | 601 km |
Distance from West Virginia to Pennsylvania | 402 km |
San Angelo
San Angelo is located in United States.
GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
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Latitude | 31.46377 |
Longitude | -100.43704 |
Altitude | 564 m |
Country | United States |
San Angelo Distances to Cities
San Angelo | Distance |
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Distance from San Angelo to Eagle | 1,948 km |
Distance from San Angelo to West Odessa | 200 km |
Distance from San Angelo to Moscow | 2,210 km |
Distance from San Angelo to Twin Falls | 1,749 km |
Distance from San Angelo to Albany Or | 2,455 km |