Distance from Washington, D.C. to San Leandro
Distance from Washington, D.C. to San Leandro is 3,907 kilometers. This air travel distance is equal to 2,428 miles.
The air travel (bird fly) shortest distance between Washington, D.C. and San Leandro is 3,907 km or 2,428 miles.
If you travel with an airplane (which has average speed of 560 miles) from Washington, D.C. to San Leandro, It takes 4.34 hours to arrive.
Washington, D.C.
Washington, D.C. is located in United States.
| GPS Coordinates (DMS) | 38° 54´ 25.8840'' N 77° 2´ 12.7320'' W |
|---|---|
| Latitude | 38.90719 |
| Longitude | -77.03687 |
| Altitude | 22 m |
| Country | United States |
Washington, D.C. Distances to Cities
| Washington, D.C. | Distance |
|---|---|
| Distance from Washington D C to New York | 328 km |
| Distance from Washington D C to Virginia | 217 km |
| Distance from Washington D C to Maryland | 38 km |
| Distance from Washington D C to New Jersey | 260 km |
| Distance from Washington D C to North Carolina | 391 km |
San Leandro
San Leandro is located in United States.
| GPS Coordinates | 37° 43´ 29.7480'' N 122° 9´ 21.8880'' W |
|---|---|
| Latitude | 37.72493 |
| Longitude | -122.15608 |
| Altitude | 19 m |
| Country | United States |