Distance from to

Distance from Washington, D.C. to San Angelo

Distance from Washington, D.C. to San Angelo is 2,278 kilometers. This air travel distance is equal to 1,415 miles.

The air travel (bird fly) shortest distance between Washington, D.C. and San Angelo is 2,278 km= 1,415 miles.

If you travel with an airplane (which has average speed of 560 miles) from Washington, D.C. to San Angelo, It takes 2.53 hours to arrive.

Washington, D.C.

Washington, D.C. is located in United States.

GPS Coordinates (DMS)38° 54´ 25.8840'' N
77° 2´ 12.7320'' W
Latitude38.90719
Longitude-77.03687
Altitude22 m
CountryUnited States

Washington, D.C. Distances to Cities

Washington, D.C.Distance
Distance from Washington D C to New York328 km
Distance from Washington D C to Virginia217 km
Distance from Washington D C to Maryland38 km
Distance from Washington D C to New Jersey260 km
Distance from Washington D C to North Carolina391 km

San Angelo

San Angelo is located in United States.

GPS Coordinates31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Latitude31.46377
Longitude-100.43704
Altitude564 m
CountryUnited States

San Angelo Distances to Cities

San AngeloDistance
Distance from San Angelo to Eagle1,948 km
Distance from San Angelo to West Odessa200 km
Distance from San Angelo to Moscow2,210 km
Distance from San Angelo to Twin Falls1,749 km
Distance from San Angelo to Albany Or2,455 km

Map of Washington, D.C.

Map of San Angelo