Distance from Warrensburg to Oklahoma City
Distance from Warrensburg to Oklahoma City is 497 kilometers. This air travel distance is equal to 309 miles.
The air travel (bird fly) shortest distance between Warrensburg and Oklahoma City is 497 km or 309 miles.
If you travel with an airplane (which has average speed of 560 miles) from Warrensburg to Oklahoma City, It takes 0.55 hours to arrive.
Warrensburg
Warrensburg is located in United States.
| GPS Coordinates (DMS) | 38° 45´ 46.0440'' N 93° 44´ 9.7800'' W |
|---|---|
| Latitude | 38.76279 |
| Longitude | -93.73605 |
| Altitude | 270 m |
| Country | United States |
Warrensburg Distances to Cities
| Warrensburg | Distance |
|---|---|
| Distance from Warrensburg to Dallas | 719 km |
| Distance from Warrensburg to Virginia Beach | 1,576 km |
| Distance from Warrensburg to Iowa City | 373 km |
| Distance from Warrensburg to Los Angeles | 2,252 km |
| Distance from Warrensburg to West Lafayette | 615 km |
Oklahoma City
Oklahoma City is located in United States.
| GPS Coordinates | 35° 28´ 3.2160'' N 97° 30´ 59.1480'' W |
|---|---|
| Latitude | 35.46756 |
| Longitude | -97.51643 |
| Altitude | 395 m |
| Country | United States |
Oklahoma City Distances to Cities
| Oklahoma City | Distance |
|---|---|
| Distance from Oklahoma City to Dallas | 305 km |
| Distance from Oklahoma City to Ponca City | 143 km |
| Distance from Oklahoma City to Owasso | 174 km |
| Distance from Oklahoma City to Memphis | 680 km |
| Distance from Oklahoma City to Houston | 664 km |