Distance from Vermont to Seymour
Distance from Vermont to Seymour is 1,268 kilometers. This air travel distance is equal to 788 miles.
The air travel (bird fly) shortest distance between Vermont and Seymour is 1,268 km or 788 miles.
If you travel with an airplane (which has average speed of 560 miles) from Vermont to Seymour, It takes 1.41 hours to arrive.
Vermont
Vermont is located in United States.
| GPS Coordinates (DMS) | 44° 33´ 31.6800'' N 72° 34´ 40.2240'' W |
|---|---|
| Latitude | 44.55880 |
| Longitude | -72.57784 |
| Altitude | 245 m |
| Country | United States |
Vermont Distances to Cities
| Vermont | Distance |
|---|---|
| Distance from Vermont to Boston | 274 km |
| Distance from Vermont to Massachusetts | 258 km |
| Distance from Vermont to California | 3,997 km |
| Distance from Vermont to Pennsylvania | 530 km |
| Distance from Vermont to Virginia | 942 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |