Distance from Utah to San Angelo
Distance from Utah to San Angelo is 1,301 kilometers. This air travel distance is equal to 808 miles.
The air travel (bird fly) shortest distance between Utah and San Angelo is 1,301 km= 808 miles.
If you travel with an airplane (which has average speed of 560 miles) from Utah to San Angelo, It takes 1.44 hours to arrive.
Utah
Utah is located in United States.
| GPS Coordinates (DMS) | 39° 19´ 15.5280'' N 111° 5´ 37.4280'' W |
|---|---|
| Latitude | 39.32098 |
| Longitude | -111.09373 |
| Altitude | 2457 m |
| Country | United States |
Utah Distances to Cities
| Utah | Distance |
|---|---|
| Distance from Utah to Las Vegas | 499 km |
| Distance from Utah to Idaho | 608 km |
| Distance from Utah to Arizona | 585 km |
| Distance from Utah to Wyoming | 525 km |
| Distance from Utah to Hawaii | 4,755 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |