Distance from Topeka to San Angelo
Distance from Topeka to San Angelo is 946 kilometers. This air travel distance is equal to 588 miles.
The air travel (bird fly) shortest distance between Topeka and San Angelo is 946 km= 588 miles.
If you travel with an airplane (which has average speed of 560 miles) from Topeka to San Angelo, It takes 1.05 hours to arrive.
Topeka
Topeka is located in United States.
| GPS Coordinates (DMS) | 39° 2´ 53.9880'' N 95° 40´ 40.9440'' W |
|---|---|
| Latitude | 39.04833 |
| Longitude | -95.67804 |
| Altitude | 306 m |
| Country | United States |
Topeka Distances to Cities
| Topeka | Distance |
|---|---|
| Distance from Topeka to St Louis | 478 km |
| Distance from Topeka to Omaha | 246 km |
| Distance from Topeka to San Francisco | 2,331 km |
| Distance from Topeka to Hannibal | 379 km |
| Distance from Topeka to Los Angeles | 2,089 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |