Distance from to

Distance from Shenandoah to Jefferson City

Distance from Shenandoah to Jefferson City is 913 kilometers. This air travel distance is equal to 567 miles.

The air travel (bird fly) shortest distance between Shenandoah and Jefferson City is 913 km= 567 miles.

If you travel with an airplane (which has average speed of 560 miles) from Shenandoah to Jefferson City, It takes 1.01 hours to arrive.

Shenandoah

Shenandoah is located in United States.

GPS Coordinates (DMS)30° 24´ 4.6800'' N
91° 0´ 3.3840'' W
Latitude30.40130
Longitude-91.00094
Altitude14 m
CountryUnited States

Shenandoah Distances to Cities

ShenandoahDistance
Distance from Shenandoah to Omaha1,284 km
Distance from Shenandoah to Nashville750 km
Distance from Shenandoah to Cedar Rapids1,289 km
Distance from Shenandoah to Oklahoma City828 km
Distance from Shenandoah to Lancaster Ca2,585 km

Jefferson City

Jefferson City is located in United States.

GPS Coordinates38° 34´ 36.1200'' N
92° 10´ 24.6720'' W
Latitude38.57670
Longitude-92.17352
Altitude195 m
CountryUnited States

Jefferson City Distances to Cities

Jefferson CityDistance
Distance from Jefferson City to Sacramento2,544 km
Distance from Jefferson City to Boston1,834 km
Distance from Jefferson City to San Francisco2,640 km
Distance from Jefferson City to Los Angeles2,386 km
Distance from Jefferson City to Dallas767 km