Distance from Shenandoah to Jefferson City
Distance from Shenandoah to Jefferson City is 913 kilometers. This air travel distance is equal to 567 miles.
The air travel (bird fly) shortest distance between Shenandoah and Jefferson City is 913 km or 567 miles.
If you travel with an airplane (which has average speed of 560 miles) from Shenandoah to Jefferson City, It takes 1.01 hours to arrive.
Shenandoah
Shenandoah is located in United States.
| GPS Coordinates (DMS) | 30° 24´ 4.6800'' N 91° 0´ 3.3840'' W |
|---|---|
| Latitude | 30.40130 |
| Longitude | -91.00094 |
| Altitude | 14 m |
| Country | United States |
Shenandoah Distances to Cities
| Shenandoah | Distance |
|---|---|
| Distance from Shenandoah to Omaha | 1,284 km |
| Distance from Shenandoah to Nashville | 750 km |
| Distance from Shenandoah to Cedar Rapids | 1,289 km |
| Distance from Shenandoah to Oklahoma City | 828 km |
| Distance from Shenandoah to Lancaster Ca | 2,585 km |
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |