Distance from Seymour to Saint Paul
Distance from Seymour to Saint Paul is 893 kilometers. This air travel distance is equal to 555 miles.
The air travel (bird fly) shortest distance between Seymour and Saint Paul is 893 km or 555 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seymour to Saint Paul, It takes 0.99 hours to arrive.
Seymour
Seymour is located in United States.
GPS Coordinates (DMS) | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
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Latitude | 38.95922 |
Longitude | -85.89025 |
Altitude | 185 m |
Country | United States |
Seymour Distances to Cities
Seymour | Distance |
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Distance from Seymour In to New York City | 1,035 km |
Distance from Seymour In to Mansfield Ma | 1,288 km |
Distance from Seymour In to Fairland | 773 km |
Distance from Seymour In to Waverly | 433 km |
Distance from Seymour In to Farmington Mn | 872 km |
Saint Paul
Saint Paul is located in United States.
GPS Coordinates | 44° 56´ 39.8760'' N 93° 5´ 35.7720'' W |
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Latitude | 44.94441 |
Longitude | -93.09327 |
Altitude | 242 m |
Country | United States |
Saint Paul Distances to Cities
Saint Paul | Distance |
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Distance from Saint Paul to Bismarck | 632 km |
Distance from Saint Paul to Los Angeles | 2,463 km |
Distance from Saint Paul to San Francisco | 2,563 km |
Distance from Saint Paul to Sacramento | 2,451 km |
Distance from Saint Paul to Las Vegas | 2,096 km |