Distance from Seymour to Sacramento
Distance from Seymour to Sacramento is 3,075 kilometers. This air travel distance is equal to 1,911 miles.
The air travel (bird fly) shortest distance between Seymour and Sacramento is 3,075 km or 1,911 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seymour to Sacramento, It takes 3.41 hours to arrive.
Seymour
Seymour is located in United States.
| GPS Coordinates (DMS) | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |
Sacramento
Sacramento is located in United States.
| GPS Coordinates | 38° 34´ 53.6520'' N 121° 29´ 39.8400'' W |
|---|---|
| Latitude | 38.58157 |
| Longitude | -121.49440 |
| Altitude | 14 m |
| Country | United States |