Distance from Seymour to Austin
Distance from Seymour to Austin is 1,451 kilometers. This air travel distance is equal to 902 miles.
The air travel (bird fly) shortest distance between Seymour and Austin is 1,451 km or 902 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seymour to Austin, It takes 1.61 hours to arrive.
Seymour
Seymour is located in United States.
| GPS Coordinates (DMS) | 38° 57´ 33.1920'' N 85° 53´ 24.9000'' W |
|---|---|
| Latitude | 38.95922 |
| Longitude | -85.89025 |
| Altitude | 185 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour In to New York City | 1,035 km |
| Distance from Seymour In to Mansfield Ma | 1,288 km |
| Distance from Seymour In to Fairland | 773 km |
| Distance from Seymour In to Waverly | 433 km |
| Distance from Seymour In to Farmington Mn | 872 km |
Austin
Austin is located in United States.
| GPS Coordinates | 30° 16´ 1.7400'' N 97° 44´ 35.0160'' W |
|---|---|
| Latitude | 30.26715 |
| Longitude | -97.74306 |
| Altitude | 165 m |
| Country | United States |
Austin Distances to Cities
| Austin | Distance |
|---|---|
| Distance from Austin Tx to San Francisco | 2,418 km |
| Distance from Austin Tx to Dallas | 293 km |
| Distance from Austin Tx to Santa Fe | 973 km |
| Distance from Austin Tx to Honolulu | 6,043 km |
| Distance from Austin Tx to Boston | 2,729 km |